ext4: correctly zero filename

Since ALLOC_CACHE_ALIGN_BUFFER declares a char* for filename
sizeof(filename) is not the size of the buffer. Use the already
known length instead.

cc: Uma Shankar <[email protected]>
cc: Manjunatha C Achar <[email protected]>
cc: Marek Vasut <[email protected]>
Signed-off-by: Jeroen Hofstee <[email protected]>
Acked-by: Marek Vasut <[email protected]>

diff --git a/fs/ext4/ext4_write.c b/fs/ext4/ext4_write.c
index c42add9a7ea95d09543b4938d42668ed03128e73..648a59672c31eec1fcd0b409a185eb079670004a 100644 (file)
--- a/fs/ext4/ext4_write.c
+++ b/fs/ext4/ext4_write.c
@@ -840,7 +840,7 @@ int ext4fs_write(const char *fname, unsigned char *buffer,
        unsigned int ibmap_idx;
        struct ext_filesystem *fs = get_fs();
        ALLOC_CACHE_ALIGN_BUFFER(char, filename, 256);
-       memset(filename, 0x00, sizeof(filename));
+       memset(filename, 0x00, 256);
 
        g_parent_inode = zalloc(sizeof(struct ext2_inode));
        if (!g_parent_inode)